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anonymous

  • 4 years ago

Derivative Problem: If you're finding the derivative of t^3 isn't it 3t^3 instead of 3t^2 because you take t^3 = t(3t^2) so when you foil it 3t^2 * t = 3t^3 but if I'm wrong can someone please explain (:

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  1. anonymous
    • 4 years ago
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    if you did that you would have to use the product rule so it is 3t^2

  2. anonymous
    • 4 years ago
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    are you familiar with the product rule?

  3. anonymous
    • 4 years ago
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    is it 3t^2 because when you write it out it's like 1(3t^2) instead of t(3t^2)?

  4. anonymous
    • 4 years ago
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    And I just learned the product rule last class, so I'm still eehhh about it.

  5. anonymous
    • 4 years ago
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    well, personally I would just never pull out the t. I would leave it as t^3 , there would be no need to pull out a t. so (d/dt)t^3=3t^2

  6. anonymous
    • 4 years ago
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    if you wanted to do the product rule of t*t^2 it would be (d/dt t)(t^2)+(t)(d/dt t^2)

  7. anonymous
    • 4 years ago
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    so 1(t^2)+t(2t)

  8. anonymous
    • 4 years ago
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    or t^2 +2t^2 = 3t^2 .. notice how we get the same answer.

  9. TuringTest
    • 4 years ago
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    are you trying to apply the product rule or the chain rule here?

  10. anonymous
    • 4 years ago
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    that was just the product rule. you don't need either.

  11. TuringTest
    • 4 years ago
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    If it's the product rule matt already covered it if it's the chain rule, then note that the inner function is t and d/dt(t)=1 so it would be d/dt(t^3)=3t^2(1)=3t^2 so as matt said, neither are necessary

  12. anonymous
    • 4 years ago
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    it was the product rule.

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