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anonymous

  • 4 years ago

calculate the energy in joules and calories required to heat 25.0 g of water from 12.5C to 25.7C

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  1. JFraser
    • 4 years ago
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    the heat (Q) required to raise the temp of a substance is:\[Q = m*C{_p}* \Delta T\] where m is the mass of the object (25.0g in this case), Cp is the specific heat capacity of the substance (for water Cp = 1.00cal/gC, or 4.18J/gC(, and Dt is the change in temp. You'll have to solve this twice, once with the Cp in calories, and once with the Cp in joules.

  2. anonymous
    • 4 years ago
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    i got 1380.72

  3. anonymous
    • 4 years ago
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    i only have a question if you don't mind helping me. i will be able to apply this to future problems. how can i figure out the different varations of that forumla you gave me?

  4. anonymous
    • 4 years ago
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    *how will i be able

  5. anonymous
    • 4 years ago
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    like in this example they ask for the J and Cal. later on they will ask me for the mass or the change in temp maybe. how can i flip stuff around?

  6. JFraser
    • 4 years ago
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    there's 4 pieces to this equation, you'll always have to be given 3 of them

  7. anonymous
    • 4 years ago
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    ah ok.

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