A sphere of clay is shape into a solid cylindrical figure. If the cylindrical figure is to be 5 cm high with a base radius of 4 cm, find the radius of the initial sphere of clay

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A sphere of clay is shape into a solid cylindrical figure. If the cylindrical figure is to be 5 cm high with a base radius of 4 cm, find the radius of the initial sphere of clay

Mathematics
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\[V _{c}=\pi r^2h \]
oh
wait

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Other answers:

What does Vc stand for?
\[V _{c}=\pi (4)^2(5)=80\pi cm ^{3}\]
Volume of the cylinder
so then the answer would be 3.14X462x5?
i mean 3.14X4^2X5
So the sphere must have had the same volume. But the volume of a sphere is: \[V=\frac{4}{3}\pi r^3=80\pi\]
So we need to solve that for the radius of the sphere
i tried the method, its just that im not sure what the answer is, thank you for helping and all.
its just 3 problems which i dont get, i did the rest on my own.
We are not done yet. Why did you put in the answer?
i didnt put the answer
3.91 is the answer
i got 3.93, are you sure its right?
It's the 3rd root of 60. I got 3.91
thank you so much, i just have 2 more problems then im finished.
Good for you.
Wait can you tell me if i did this right: Find the volume of a cylinder of height 16 cm and base diameter 40 cm. I got 8038 CM cubed.
Hand on. I;m on the phone.
k
V= pi (20)^2(16)=20106.19
wait so was my answer correct, because i think i did the right way
Compare it with mine.
ok
Did you use 20 for the radius instead of 40?
i added it up and the answer was: 20096 cm
i think i might have used it
There's nothing to add.
so this is the answer: 20106.19?
The question asked for the radius of the sphere. The radius of the sphere is 3.91 cm
hey your back?
yep
Just got off the phone.
ok so i did this problem by myself, tell me what you think:
ok
Find the volume of an equilateral triangular prism with triangles of side 4 cm and length 10 cm
i did area x height to get the answer so:
So what did you get for the area of the triangle?
so i got 12 rounded
i really got 11.994 so i rounded to 12, would that be right?
That seems to big.
oh
what would the answer be then?
Here is the triangle: |dw:1328744624957:dw|
ya i did that
\[A=\frac{1}{2}bh\]
so height equals=3.464, then to get area base X height so 3.464X2
/2
\[A=\frac{1}{2}(4)(2\sqrt{3})=4\sqrt{3}=6.93\]
oh so the answer is 6.93?
That is the area of the base. To get the volume, you have to multiply that by the height.
ok
so the answer is approximately 24?
10(6.93)=69.3
i was wrong?
|dw:1328744898001:dw|
See that picture? You have to take the area of the triangle and multiply it by the height of the prism which is 10
but i did 6.93x the height, which is 3.464, and i got 24, is that right?
Do you see that picture?????? The HEIGHT OF THE PRISM IS 10.
Multiply the AREA OF THE TRIANGLE BY THE HEIGHT OF THE PRISM
ok thx
The height of the prism is 10
yw
|dw:1328745230091:dw|
The shaded area of that
What part is shaded?
all of the inside
|dw:1328745481111:dw|
Add the two areas together. 120+24 = 144
Ok, great, thats what i got
|dw:1328745544210:dw|
find the area
|dw:1328745737456:dw|
Is that a 39 or not?
39 and 34 are to big dont you think?
Yes. What is that number you wrote on the left side of the drawing?
oh thats 9
|dw:1328745967893:dw|
Is that it?
ya i think 7 and 4 are more reasponsible, considering thats what i got as well. Then i did 7X4+2X5, getting 38 m
Is that correct?
hello?
That's what I got.

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