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anonymous
 4 years ago
The volume of a cone (v=1/3 pi^2h) is increasing at the rate of 28pi cubic inches per second. At the instant when the radius 'r' of the cone is 3 inches, its volume is 12pi cubic inches and the radius is increasing at .5 inch per second
A. At the instant when the radius of the cone is 3 inches, what is the rate of change of the area of its base?
anonymous
 4 years ago
The volume of a cone (v=1/3 pi^2h) is increasing at the rate of 28pi cubic inches per second. At the instant when the radius 'r' of the cone is 3 inches, its volume is 12pi cubic inches and the radius is increasing at .5 inch per second A. At the instant when the radius of the cone is 3 inches, what is the rate of change of the area of its base?

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