help w/ quadratic equation: -0.01x^2+50x-62100=0

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help w/ quadratic equation: -0.01x^2+50x-62100=0

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a=-0.01 b=50 c=62100 http://www.google.ca/imgres?imgurl=http://www.crewtonramoneshouseofmath.com/images/quad_eq.gif&imgrefurl=http://www.crewtonramoneshouseofmath.com/quadratic-formula.html&h=144&w=216&sz=1&tbnid=CthzqmDGhvueTM:&tbnh=69&tbnw=104&prev=/search%3Fq%3Dquadratic%2Bformula%26tbm%3Disch%26tbo%3Du&zoom=1&q=quadratic+formula&docid=B_90q8kTbbTW8M&sa=X&ei=-g0zT76yNoW42QXii8HbBw&ved=0CFYQ9QEwBw&dur=177
since there is a +or- you will get 2 answers for x
i know but i need help solving it

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Other answers:

-0.01x^2+50x-62100=0 x^2-5000x+6210000=0 \[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
Zed can help you with that, but it's literally just plugging in the values for a b c into the equation
Here a=1, b=-5000 and c=6210000 \[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]\[=\frac{5000 \pm \sqrt{(-5000)^2-4*1*6210000}}{2*1}\]\[=\frac{5000 \pm \sqrt{25000000-24840000}}{2}\]\[=\frac{5000 \pm \sqrt{160000}}{2}\]\[=\frac{5000 \pm 400}{2}\]\[=2500 \pm 200\] So x=2700 or x=2300

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