Can someone help me with the following integral:

- anonymous

Can someone help me with the following integral:

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- anonymous

##### 1 Attachment

- anonymous

int:sin(x)^3cos(x)
use u substitution
let u = sinx
du =cosxdx
new integral:
int:u^3du
=(1/4)u^4+C
plug back in sinx for u
sin^4(x)/4+c

- anonymous

http://integrals.wolfram.com/index.jsp?expr=sin%28x%29%5E3cos%28x%29&random=false

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## More answers

- anonymous

that's what it looks like in better symbol form when finished. open for any questions

- anonymous

Thank you very much. I tryied so hard and I could not find the answer. Thank you so much

- anonymous

Your welcome, glad to help.

- anonymous

any others?

- anonymous

Yeah I have problem with three. well now two

- anonymous

can you help me with them?

- anonymous

Im just learning how to integrate

- anonymous

I can try, aha but i won't promise! ;P

- anonymous

in other words i'll do my best

- anonymous

let me post the other two

- anonymous

okay

- anonymous

Can you see it?

- anonymous

no....

- anonymous

Ok let me try again

- anonymous

##### 1 Attachment

- anonymous

what about now?

- anonymous

yeah i can see it, okay this one is a little more difficult . you have to use trigonometric identities

- anonymous

Do you think you can solve it?

- anonymous

let me think for a sec

- anonymous

ok :)

- anonymous

that's kind of a difficult one, however if you want to see all the steps.. i won't do them personally but here is something you can refer to

- anonymous

http://www.wolframalpha.com/widgets/view.jsp?id=dc816cd78d306d7bda61f6facf5f17f7

- anonymous

i guess it doesn't take you to the answer i put in, so just enter cos^7(x)

- anonymous

you can click see steps for indefinite integral.

- anonymous

are you sure that there isn't a sin, in your problem? that would make it so much easier

- anonymous

Im learning calculus so it will be awsome if you show me how to integrate with sin as well.

- anonymous

well i can do my best, i wasn't really able to help with the last one really though, if the integrand has sin and cos in it, that is easier

- anonymous

I think I found a way to solve it. I need to try a little bit harder. Any question I will let you know my friend

- anonymous

sounds good! good luck

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