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int:sin(x)^3cos(x) use u substitution let u = sinx du =cosxdx new integral: int:u^3du =(1/4)u^4+C plug back in sinx for u sin^4(x)/4+c
that's what it looks like in better symbol form when finished. open for any questions
Thank you very much. I tryied so hard and I could not find the answer. Thank you so much
Your welcome, glad to help.
Yeah I have problem with three. well now two
can you help me with them?
Im just learning how to integrate
I can try, aha but i won't promise! ;P
in other words i'll do my best
let me post the other two
Can you see it?
Ok let me try again
what about now?
yeah i can see it, okay this one is a little more difficult . you have to use trigonometric identities
Do you think you can solve it?
let me think for a sec
that's kind of a difficult one, however if you want to see all the steps.. i won't do them personally but here is something you can refer to
i guess it doesn't take you to the answer i put in, so just enter cos^7(x)
you can click see steps for indefinite integral.
are you sure that there isn't a sin, in your problem? that would make it so much easier
Im learning calculus so it will be awsome if you show me how to integrate with sin as well.
well i can do my best, i wasn't really able to help with the last one really though, if the integrand has sin and cos in it, that is easier
I think I found a way to solve it. I need to try a little bit harder. Any question I will let you know my friend
sounds good! good luck