An unmarked police car traveling a constant 85km/hr is passed by a speeder traveling 140km/hr. About 3.00s after the speeder passes, the police officer steps on the accelerator, if the police car's acceleration is 1.80m/s^2 , how much time passes before the police car ovetakes the speeder after the speeder passes?(assumed moving at constant speed)
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
This is a physics question involving kinematic equations. So far I've set up my problem as such: t = 3.00s, v-speeder140km/h, v-p: 85km/h. a-p: 1.80m/s^2. V stands for velocity of speeder and police car and a stands for acceleration.
I'm thinking that I would need to use this kinematics equation: d= vt+1/2at^2