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anonymous

  • 4 years ago

so in geometry, were going over lines that meet inside, outside, or on the circle. now i got to the point where i has the equation set up but cant figure it out. the equation is "8X+X^2=36" help?

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  1. anonymous
    • 4 years ago
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    Can you please explain a bit more, did you try use the formula for solving quadratic equation?

  2. anonymous
    • 4 years ago
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    i will draw it. hold on

  3. anonymous
    • 4 years ago
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    |dw:1328752131866:dw|

  4. anonymous
    • 4 years ago
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    so line ar is 9, rb is 4 and km is 8. i need to find rk. i think i set the equation up right, but i may be wrong

  5. anonymous
    • 4 years ago
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    The length of the radius should be given

  6. anonymous
    • 4 years ago
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    its not. i gave you all the information the book gave me.

  7. anonymous
    • 4 years ago
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    I am not sure for all the information given one can set up any equation, can you please show me work

  8. anonymous
    • 4 years ago
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    Hey I am sorry, length of radius is given it is KM

  9. anonymous
    • 4 years ago
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    yeah the equation is ok. Let us see how to solve the equation \[x ^{2} + 8x - 36= 0\] => \[x = (-8 \pm \sqrt{8^{2} - 4*1*(-36)}) / 2 * 1\] (using quadratic equation) Since X here denote length, we will take only the positive value, hence, \[x = (-8 + \sqrt{208}) * 0.5= 3.211\]

  10. anonymous
    • 4 years ago
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    well i get that. but the book says its 5.3 :/

  11. anonymous
    • 4 years ago
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    i dont understand how it got 5.3 in any way shape or form

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