## anonymous 4 years ago (2/3)^abslx+2l=(81/16)^-3

1. anonymous

$(\frac{81}{16})^{-3}=(\frac{16}{81})^3=(\frac{2^4}{3^4})^3$ $=(\frac{2}{3})^{12}$

2. anonymous

this tells you $|x+2|=12$ so $x=2=12$ or $x+2=-12$