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The distance is zero? How can that be?
That's what I think it looks like.
Yeah, but distance is always positive so how can you add three positive distances and get zero?
Yes, you should post them as vectors.
I'll try to get an answer to this for you. No promises though
Thanks for trying then.
I have your solution
gimme a sec.
I don't seem to follow the process.
I'm sorry to hear that. I thought it would have been obvious
Is there a specific order you did this from?
1. ABC is an equilateral Triangle 2. Segments OA, OB and OC are equidistant from the center 3. AB = BC = AC 4. AB, BC, and AC are labeled side s. 5. OA, OB and OC bisect angles A, B, and C. 6. OA bisects BC. 7. Create point D. 8. BD = -s/2 ; CD = s/2 9. x compnent OA = 0 because it's x component has no distance x compoent OB = -s/2 x component OC = s/2 10. x component 0 + s/2 - s/2 = 0 11. y component OB = s/2 tan(30) = -sqrt(3)/6 y component OB = y component OC = -sqrt(3)/6 12. y component OA = OA = OB 13. OB = s/2 cos(30) = s*sqrt(3)/3 14. y component OA + OB + OC = sqrt(3)/3 - sqrt(3)/6 - sqrt(3)/6 = 0 QED
I'll take questions concerning specific steps you have questions on
I'm just interpreting it right now. I guess I'm good for now. Thanks.