anonymous
  • anonymous
the series ((-1)^n+1)(x-2)^n)/n .... the interval of convergence is 1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
another end point one, this time i do it with paper before typing
anonymous
  • anonymous
\[|x-2|<1\]
anonymous
  • anonymous
ok got it

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anonymous
  • anonymous
now we try replacing x by 1 btw you have done all the hard work, the rest should be the easy part
anonymous
  • anonymous
at x=1 i think it is \[\sum_{?}^{?} (-1)^{n+1}(-1)^{n}\div n\] ???
saifoo.khan
  • saifoo.khan
anonymous
  • anonymous
ok very smilar to the last one
anonymous
  • anonymous
but this time we don't do anything stupid \[(-1)^{n+1}(-1)^n=(-1)^{2n+1}=-1\]
anonymous
  • anonymous
on account of \[2n+1\] is odd.
anonymous
  • anonymous
so does not converge at x = 1
anonymous
  • anonymous
what do you want to bet it does converge at x = 3?
anonymous
  • anonymous
.ah! um a lot? haha.
anonymous
  • anonymous
yeah well we can just about visualize it because it is the same as the last one. this time you get \[(-1)^{n+1}\times 1=(-1)^{n+1}\]so we are in good shape
anonymous
  • anonymous
thank you! another question...
anonymous
  • anonymous
this one alternates in other words, whereas the other one does not
anonymous
  • anonymous
keep posting
anonymous
  • anonymous
you got zarkon watching so if i mess up he will step in wish he had stepped in to the last one so i wouldn't have made a fool out of myself

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