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but you are a higher level than zarkon haha.

hell no
term by term

is (-1)^n+1(x-2)^n-1 right?

yes i believe so , let me write it so i don't do anything silly
are we starting at n = 0 or n = 1?

yes that is right. what you have

1. okay and then i got the interval of that to be 1

same

oh but not at the endpoints of course

next question...can you explain how to find the power series of a function?

i can show you a trick for that one if you like

well maybe not

yes please! i have an exam tomorrow and i need as much help as possible.

but if you have an exam forget that mess

er
\[1+\frac{1}{4}x+\frac{\frac{1}{4}-1}{2!}x^2\]

\[+\frac{(\frac{1}{4}-1)(\frac{1}{4}-2)}{3!}x^3 +...\]

probably some algebra will turn up a nice pattern

but i dont understand the maclaurin part?

that is the maclaurin series

expand about zero, get
\[a_0+a_1x+a_2x^2+a_3x^3 + ...\]

wait what about the thing where you take the derivative multiple times and plug it in?

the hint was "binomial" formula

good luck

that first part of the tip is so true! anyway thank you so much. you are a lifesaver. seriously.

your quite welcome, and really good luck and relax
and don't stay up all night studying