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anonymous

  • 4 years ago

Can you help me to solve the following integer?

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  1. anonymous
    • 4 years ago
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    |dw:1328759896228:dw|

  2. bahrom7893
    • 4 years ago
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    Let u = x^2

  3. bahrom7893
    • 4 years ago
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    hold on ill draw, this is inverse sin

  4. anonymous
    • 4 years ago
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    ok thanks

  5. bahrom7893
    • 4 years ago
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    |dw:1328760042213:dw| nevermind it was double u-sub

  6. anonymous
    • 4 years ago
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    ok

  7. bahrom7893
    • 4 years ago
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    hmm no.. hold on, i'm sure it's one of these subs..

  8. anonymous
    • 4 years ago
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    Dont worry, I have been trying to solve it for more that an hour. So I will wait

  9. anonymous
    • 4 years ago
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    It doesn't look like a double u-sub...? Or were you thinking that it was a trig sub?

  10. bahrom7893
    • 4 years ago
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    yea i think so..

  11. anonymous
    • 4 years ago
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    that works though, your double u-sub is fine

  12. bahrom7893
    • 4 years ago
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    Wolf to the rescue!

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  13. anonymous
    • 4 years ago
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    Ew, a double u-sub and a tan integral. NO, DON'T GIVE ME A MEDAL. I didn't do anything lol.

  14. anonymous
    • 4 years ago
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    You deserve that anyway

  15. anonymous
    • 4 years ago
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    i don't think you have to do a tan integral do you? what if you u just went w = u^2-1 dw =2udu dw/2u=du

  16. anonymous
    • 4 years ago
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    |dw:1328760546289:dw|

  17. anonymous
    • 4 years ago
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    solve that and then do all the subbing

  18. anonymous
    • 4 years ago
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    dont get it

  19. anonymous
    • 4 years ago
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    sorry, can you post it?

  20. anonymous
    • 4 years ago
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    does that make sense to anyone else, cause i could be way out

  21. anonymous
    • 4 years ago
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    It doesn't cancel the u outside the sqrt in the denominator, unless I'm mistaken. Which is why a tan is necessary.

  22. anonymous
    • 4 years ago
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    yeah, wishful thinking i guess. looks wrong now that i think about it. Sorry you gotsa suffer through the trig integral

  23. anonymous
    • 4 years ago
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    Its ok

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