At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
Let u = x^2
hold on ill draw, this is inverse sin
|dw:1328760042213:dw| nevermind it was double u-sub
hmm no.. hold on, i'm sure it's one of these subs..
Dont worry, I have been trying to solve it for more that an hour. So I will wait
It doesn't look like a double u-sub...? Or were you thinking that it was a trig sub?
yea i think so..
that works though, your double u-sub is fine
Ew, a double u-sub and a tan integral. NO, DON'T GIVE ME A MEDAL. I didn't do anything lol.
You deserve that anyway
i don't think you have to do a tan integral do you? what if you u just went w = u^2-1 dw =2udu dw/2u=du
solve that and then do all the subbing
dont get it
sorry, can you post it?
does that make sense to anyone else, cause i could be way out
It doesn't cancel the u outside the sqrt in the denominator, unless I'm mistaken. Which is why a tan is necessary.
yeah, wishful thinking i guess. looks wrong now that i think about it. Sorry you gotsa suffer through the trig integral