## anonymous 4 years ago converge or diverge? An = (1-3/n)^2n

1. anonymous

Most likely Converge.

2. anonymous

Can you prove it? Im stuck at lny = ln(1-3n)/(1/2n)

3. Zarkon

$\left(1-\frac{3}{n}\right)^{2n}$ after taking the natural log you will have $\frac{\ln\left(1-\frac{3}{n}\right)}{\frac{1}{2n}}$ now use L'Hospitals rule