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anonymous

  • 4 years ago

Write all of the following statement(s) that apply to the following polynomial: -5x^3 + 2x^2 – 7 It is a binomial. It cannot be evaluated at x = -1/3 It has a degree of 3. It is cubic.

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  1. anonymous
    • 4 years ago
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    It is a binomial I guess.

  2. anonymous
    • 4 years ago
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    thats it

  3. anonymous
    • 4 years ago
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    Yes that's it, anything else?

  4. anonymous
    • 4 years ago
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    so just say its that

  5. anonymous
    • 4 years ago
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    Lolz wow

  6. IsTim
    • 4 years ago
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    I think it's everything but I haven't checked "It cannot be evaluated at x = -1/3". IF you wanna check ,sub that in the equation, and see if the result is good.

  7. anonymous
    • 4 years ago
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    I am lost

  8. IsTim
    • 4 years ago
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    I don't think its a binomial, but what do I know.

  9. IsTim
    • 4 years ago
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    "It is a binomial." Forgot what binomial is... "It cannot be evaluated at x = -1/3" Sub x=-1/3 into -5x^3 + 2x^2 – 7. It has a degree of 3.- I think of -5x^3. "It is cubic." I think of "-5x^3 ".

  10. anonymous
    • 4 years ago
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    I been told you it's a binomial. Wow.

  11. IsTim
    • 4 years ago
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    Looks to me as a trinomial, or greater.

  12. anonymous
    • 4 years ago
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    It's a binomial dude.

  13. IsTim
    • 4 years ago
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    What's its binomial form? (x-a)(x-b) or whatever? It looks to be that right?

  14. IsTim
    • 4 years ago
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    Sorry, getting off what the questioner wants, but I really should learn this.

  15. anonymous
    • 4 years ago
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    Than Tim don't confuse her man. It's a binomial for the 100 th time I said it. lol

  16. anonymous
    • 4 years ago
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    u already confused me

  17. bahrom7893
    • 4 years ago
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    ITS NOT BINOMIAL!

  18. bahrom7893
    • 4 years ago
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    HELLOOO BI means two! It's cubic and has a degree of 3, it's defined everywhere, so undefined at 1/3 is false too

  19. bahrom7893
    • 4 years ago
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    C and D are the options

  20. anonymous
    • 4 years ago
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    so the third and fourth one are correct

  21. IsTim
    • 4 years ago
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    You gotta sub in the value to check the second one. It's very possible for it to work.

  22. IsTim
    • 4 years ago
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    I'm not doing it myself cause I'm working on something else.

  23. bahrom7893
    • 4 years ago
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    Listen the only way it wouldnt work if u had a denominator with x + 1/3 cuz u'd get a 0 on the denominator.. or something like a negative under sqrt. YES THE ANSWER IS 3 AND 4.

  24. IsTim
    • 4 years ago
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    Ok. Makes sense.

  25. IsTim
    • 4 years ago
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    Didn't check it out personally (mathematically).

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