## anonymous 4 years ago Simplify the following product of complex numbers.(-3 + 2i) · (-4 – 8i). I got 12-16i is this correct or am I doing something wrong?

1. anonymous

think there is something wrong here

2. anonymous

ok could you please explain what I am doing wrong oh wait it is 12-16i^2

3. anonymous

$-3\times -4+2\times 8=28$

4. anonymous

12-24i-8i+16, 28-32i, or am I being dumb?

5. anonymous

omg I am so confused now

6. anonymous

$(-3 + 2i) · (-4 – 8i)$ $(-3\times -4+2\times 8)+(2\times -4-3(-8))i$

7. anonymous

if that is confusing you can multiply it out just like you would $(-3 + 2x) · (-4 – 8x)$

8. anonymous

But remember x^2, i^2 is -1.

9. anonymous

aka first outer inner last $12 +24i-8i-16i^2$ $12+16i+16$ $28+16i$

10. anonymous

Oh right, I failed to multiply -3 and -8i correctly. Woops. Lol.

11. anonymous

I multiplied -3*-4=12 then got multiplied 2i *8i=16i^2 I am completely conpletely confused feel like an idiot math has never had me so dumb founded

12. anonymous

I get it!!!! I was not solving the whole problem got it THANK YOU THANKYOU SO MUCH!!!!