Simplify the following product of complex numbers.(-3 + 2i) · (-4 – 8i). I got 12-16i is this correct or am I doing something wrong?

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Simplify the following product of complex numbers.(-3 + 2i) · (-4 – 8i). I got 12-16i is this correct or am I doing something wrong?

Mathematics
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think there is something wrong here
ok could you please explain what I am doing wrong oh wait it is 12-16i^2
\[-3\times -4+2\times 8=28\]

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12-24i-8i+16, 28-32i, or am I being dumb?
omg I am so confused now
\[(-3 + 2i) · (-4 – 8i)\] \[(-3\times -4+2\times 8)+(2\times -4-3(-8))i\]
if that is confusing you can multiply it out just like you would \[(-3 + 2x) · (-4 – 8x)\]
But remember x^2, i^2 is -1.
aka first outer inner last \[12 +24i-8i-16i^2\] \[12+16i+16\] \[28+16i\]
Oh right, I failed to multiply -3 and -8i correctly. Woops. Lol.
I multiplied -3*-4=12 then got multiplied 2i *8i=16i^2 I am completely conpletely confused feel like an idiot math has never had me so dumb founded
I get it!!!! I was not solving the whole problem got it THANK YOU THANKYOU SO MUCH!!!!

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