anonymous
  • anonymous
Simplify the following product of complex numbers.(-3 + 2i) · (-4 – 8i). I got 12-16i is this correct or am I doing something wrong?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
think there is something wrong here
anonymous
  • anonymous
ok could you please explain what I am doing wrong oh wait it is 12-16i^2
anonymous
  • anonymous
\[-3\times -4+2\times 8=28\]

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anonymous
  • anonymous
12-24i-8i+16, 28-32i, or am I being dumb?
anonymous
  • anonymous
omg I am so confused now
anonymous
  • anonymous
\[(-3 + 2i) · (-4 – 8i)\] \[(-3\times -4+2\times 8)+(2\times -4-3(-8))i\]
anonymous
  • anonymous
if that is confusing you can multiply it out just like you would \[(-3 + 2x) · (-4 – 8x)\]
anonymous
  • anonymous
But remember x^2, i^2 is -1.
anonymous
  • anonymous
aka first outer inner last \[12 +24i-8i-16i^2\] \[12+16i+16\] \[28+16i\]
anonymous
  • anonymous
Oh right, I failed to multiply -3 and -8i correctly. Woops. Lol.
anonymous
  • anonymous
I multiplied -3*-4=12 then got multiplied 2i *8i=16i^2 I am completely conpletely confused feel like an idiot math has never had me so dumb founded
anonymous
  • anonymous
I get it!!!! I was not solving the whole problem got it THANK YOU THANKYOU SO MUCH!!!!

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