anonymous
  • anonymous
true / false if dropped from the top of a high building a 20 kg sphere with a radius of 20 cm will reachterminal velocity before a 10 kg sphere with the same radius
Physics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
Drag force, IIRC, is D=(1/2)CpAv^2, where C is the drag coefficient of the fluid, p is the fluid density, and A is the cross sectional area perpendicular to the direction of force. Nowhere here is mass mentioned; this is merely an upwards pointing force for all masses of the same A. The force of gravity needs to equal D. But the force of gravity is mass-reliant, a la F=ma, or F_g=mg. With a larger m comes a larger F, and as v increases similarly for both masses, it will take longer for D to meet the larger F_g. So, yes, the one with the larger mass will take longer to reach terminal velocity.
anonymous
  • anonymous
Note, though, I assumed that the drag (air resistance) were negligible for the velocity's progression as time went by. If the numbers were extreme enough that they aren't, then the answer might change.
anonymous
  • anonymous
thank you so much thanks for taking the time to make me understand i really appreciate it

Looking for something else?

Not the answer you are looking for? Search for more explanations.