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anonymous
 4 years ago
how do i find the limit
ln(x3)
x>3+
anonymous
 4 years ago
how do i find the limit ln(x3) x>3+

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TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2it's approaching from the right, so it's defined because x3 is positive and what number does lny approach as y approaches zero?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2...because x^a is always positive for x>0 we can only make it small by making 'a' large negative

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you migth think of it like this. the log is the inverse of the exponential. when would \[e^x=0\]? well never, but it would be close to zero if x went to minus infinity

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2yes it should be minus^ Igb is a bit off

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so as x goes to minus infinity, \[e^x\] goes to zero and as x goes to zero, \[\ln(x)\] goes to minus infinity
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