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anonymous

  • 4 years ago

can someone help please?

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  1. TuringTest
    • 4 years ago
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    better to just ask a question

  2. anonymous
    • 4 years ago
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    can someone help me im stumped on this problem i need help please. A computer is infected with the Sasser virus. Assume that it infects 20 other computers within 5 minutes; and that these PCs and servers each infect 20 more machines within another five minutes, etc. How long until 100 million computers are infected?

  3. bahrom7893
    • 4 years ago
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    the computer's screwed

  4. bahrom7893
    • 4 years ago
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    does it have something to do with powers turing? i suck at these types of questions

  5. anonymous
    • 4 years ago
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    logs and exponential functions

  6. TuringTest
    • 4 years ago
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    it's not my thing either...

  7. anonymous
    • 4 years ago
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    \[20^{\frac{t}{5}}=100,000,000\]

  8. TuringTest
    • 4 years ago
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    I almost came up with that!

  9. anonymous
    • 4 years ago
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    oh crap that is wrong. that will not do it

  10. TuringTest
    • 4 years ago
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    plus one in there right?

  11. anonymous
    • 4 years ago
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    because i was not counting the ones already infected

  12. TuringTest
    • 4 years ago
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    \[20^{1+\frac t5}=10000000\]

  13. TuringTest
    • 4 years ago
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    no?

  14. anonymous
    • 4 years ago
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    gotta sum this sucker up, let me see if i remember.

  15. anonymous
    • 4 years ago
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    10^8=20^5t

  16. anonymous
    • 4 years ago
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    should be \[\frac{t}{5}\] or maybe what turing said, but we are neglecting the ones infected along the way

  17. anonymous
    • 4 years ago
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    \[20+20^2+20^3+...\]

  18. anonymous
    • 4 years ago
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    so lets try \[\sum_{k=1}^n20^k=10^8\] \[\frac{20^{n+1}-1}{19}=10^8\] \[20^{n+1}=19\times 10^8\] \[(n+1)=\frac{\ln(19\times 10^8)}{\ln(20)}\]

  19. anonymous
    • 4 years ago
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    can you please explain what you have?

  20. anonymous
    • 4 years ago
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    i was summing the geomtric series \[20 + 20^2+20^3+...\] and seeing when it would equal 10^8

  21. anonymous
    • 4 years ago
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    i get approximately 7, so that means around 35 minutes

  22. anonymous
    • 4 years ago
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    so it would 20^7 how can i log it

  23. anonymous
    • 4 years ago
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    I got it 20^5t=10^8

  24. anonymous
    • 4 years ago
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    20^0t=120/4

  25. anonymous
    • 4 years ago
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    t=30

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