anonymous
  • anonymous
Twice an integer increased by fourteen is less than 5. What is the greatest solution? Please explain.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
x+14 > 5 well if you have this and solve x < 9 so i think this would be the greatest solution
anonymous
  • anonymous
answer is -5. I don't how. Please can you try again.
anonymous
  • anonymous
it's a multiple choice A. -5 B.-4 c.-4.5 D.- 4.6 E.NOTA

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anonymous
  • anonymous
o lol i forgot the 2 2x + 14 > 5 2 x > - 9 x > -9/ 2 x > - 5
anonymous
  • anonymous
Answer is A
anonymous
  • anonymous
it was 2x i forgot it XD
anonymous
  • anonymous
wow.thanks
anonymous
  • anonymous
Thank you so much!
anonymous
  • anonymous
How did you get x>-5 x > -9/ 2 x > - 5 it.s x>-4.5
Directrix
  • Directrix
Twice an**** integer ***increased by fourteen is less than 5 ----- The answer has to be an integer. I think that the problem is set up incorrectly. Twice an integer increased by fourteen is less than 5 2x + 14 IS Less Than 5. 2x + 14 < 5 2x < - 9 x < -9/2 x < -4.5 The largest INTEGER value of x that is less than -4.5 is -5.
Directrix
  • Directrix
Note: Had this work been correct: x > -9/ 2, x > - 4.5, then the answer would be -4 and not -5.

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