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anonymous

  • 4 years ago

Find y'' of \[\sqrt{x}+\sqrt{y}=1\]. I found f'= \[-\sqrt{y}/\sqrt{x}\]. I can't figure out where to go from here. Any help?

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  1. anonymous
    • 4 years ago
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    is this under implicit differentiation?

  2. anonymous
    • 4 years ago
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    yes

  3. anonymous
    • 4 years ago
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    whoops btw y' =-sqrt(y)/sqrt(x). sorry bout that.

  4. anonymous
    • 4 years ago
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    gah, I dunno if i have the energy for this right now. wolfram might have a step by stepper

  5. TuringTest
    • 4 years ago
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    why does this have to be implicit differentiation?

  6. anonymous
    • 4 years ago
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    These are the instructions I am given. Is there another way to do it?

  7. anonymous
    • 4 years ago
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    it doesn't Have to be, It just seems like a problem they would ask under that section

  8. anonymous
    • 4 years ago
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    you can also use the chain rule

  9. anonymous
    • 4 years ago
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    by manipulating the equation . here i'll get a computer to do it for you :P

  10. anonymous
    • 4 years ago
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    yes implicit differentiation is subject of the section. ty for the help. I used wolfram but I wasn't sure that i had the correct input

  11. anonymous
    • 4 years ago
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    http://calc101.com/webMathematica/derivatives.jsp#topdoit

  12. anonymous
    • 4 years ago
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    dang it didn't carry the answer. well type (1-x^(1/2))^2 into the function box

  13. anonymous
    • 4 years ago
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    it will give the first and second derivatives with steps but it's not implicit, just chain rule

  14. anonymous
    • 4 years ago
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    it will give the first and second derivatives with steps but it's not implicit, just chain rule

  15. anonymous
    • 4 years ago
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    it will give the first and second derivatives with steps but it's not implicit, just chain rule

  16. TuringTest
    • 4 years ago
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    \[y''=-\frac12y^{-1/2}x^{1/2}y'+\frac12y^{1/2}x^{-3/2}\]sub in the other guys

  17. anonymous
    • 4 years ago
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    sorry i dunno what's wrong with my computer right now, if it's sending the messages multiple times.

  18. anonymous
    • 4 years ago
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    turing, do you sub y' back into the equation for y''?

  19. TuringTest
    • 4 years ago
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    why not? It'll be messy algebraicly, but after it sub in for y again it'll be true...

  20. anonymous
    • 4 years ago
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    Ok I see thank you very much for the help.

  21. TuringTest
    • 4 years ago
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    welcome

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