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anonymous
 4 years ago
The figure shows four electrical charges located at the corners of a rectangle. Like charges, you will recall, repel each other while opposite charges attract. Charge B exerts a repulsive force (directly away from B) on charge A of 3.0 N. Charge C exerts an attractive force (directly toward C) on charge A of 6.0 N. Finally, charge D exerts an attractive force of 2.0 N on charge A.
Assuming that forces are vectors, what is the magnitude of the net force F exerted on charge A?
anonymous
 4 years ago
The figure shows four electrical charges located at the corners of a rectangle. Like charges, you will recall, repel each other while opposite charges attract. Charge B exerts a repulsive force (directly away from B) on charge A of 3.0 N. Charge C exerts an attractive force (directly toward C) on charge A of 6.0 N. Finally, charge D exerts an attractive force of 2.0 N on charge A. Assuming that forces are vectors, what is the magnitude of the net force F exerted on charge A?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you actually want me to solve the problem, or are you just looking for a hint? I can do both, but the former will take me some time to write it all down and post it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Alright, I'll do it out. Give me some time, though.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ugh, actually, I wish I could just scan my handwriting. :c This is the most annoying thing to type. Generally, though, decompose every vector force acting on charge A into its x and y components. To do this, we are given the distance between the charges. With right triangles, we can use trigonometry to find the component values. Find every component x vector acting on A and add them. The same for y. Find the final force vector by doing simple vector addition. I'm not willing to type out the work. Sorry.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1329636367752:dwyou really only need to break up one vector: the one at an angle the angle can be found using the sides of the rectangle \[F_x=2\cos\theta\]\[F_y=2\sin\theta\]the other vectors are already entirely in either the x or y, so add it all up to find your resultant vector components, as said by badreferences
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