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anonymous

  • 4 years ago

Let's say a car drives in a semicircle so that there's centripetal force. The force is the product of the car's normal force and the coefficient of static friction, apparently because there's no radial component of the car's movement. According to my textbook. But, if the car did turn its wheels to execute the semicircle, doesn't it readjust its force such that it does have a radial component?

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  1. anonymous
    • 4 years ago
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    As an extension of that, if it did have a radial component, wouldn't the centripetal force friction be the product of the car's normal force and the coefficient of kinetic friction?

  2. TuringTest
    • 4 years ago
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    There is a radial force component, otherwise it wouldn't turn. That's different from saying that is doesn't /move/ radially. Which is your claim?

  3. anonymous
    • 4 years ago
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    Oh, right, because its movement is always perpendicular to the radial force component, there will never be a radial component to the motion. Thanks.

  4. anonymous
    • 4 years ago
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    |dw:1328779889539:dw| we can see that there is diffewerent direction of acceleration hence different force operating it is only because of that radial component of acceleration mv^2/r that the car is pulled to the centre and reamains in the circle

  5. AravindG
    • 4 years ago
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    hey

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