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anonymous
 4 years ago
Find the solution of the differential equation that satisfies the following initial conditions.
dy/dx = (y/y+1)*(xsinx) , y(0) = 1
anonymous
 4 years ago
Find the solution of the differential equation that satisfies the following initial conditions. dy/dx = (y/y+1)*(xsinx) , y(0) = 1

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I know this is a seperable differential equation and I've gotten to the point where I have lny+y = sin(x)xcos(x) + C but I don't know how to isolate for the y

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.0there is no easy solution here... http://www.wolframalpha.com/input/?i=y%2Blog%28y%29+%3D+sin%28x%29xcos%28x%29%2Bc http://www.wolframalpha.com/input/?i=dy%2Fdx+%3D+%28y%2F%28y%2B1%29%29*xsin%28x%29

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=dy%2Fdx+%3D+y%2F%28y%2B1%29*%28xsinx%29+%2C+y%280%29+%3D+1
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