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King

  • 2 years ago

A baseball player hits a homerun, and the ball lands in the left field seats, which is 120 m away from the point at which the ball was hit. The ball lands with a velocity of 20 m/s at an angle of 30 degrees below horizontal. Ignoring air resistance (A) find the initial velocity and the angle above horizontal with which the ball leaves the bat; (B) find the height of the ball relatively to the ground

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  1. Mani_Jha
    • 2 years ago
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    If there is no air resistance, the parabolic path will be symmetrical, and thus it will land at the same velocity with which it left. So \[u=20 m/s and \theta=30\] The height will be \[h=u ^{2}\sin ^{2}\theta/2g\]

  2. salini
    • 2 years ago
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    it is like that concept in which when u fire a bullet vertically up,it comes down same straight line to hit u with same speed with which it went if not for air drag

  3. salini
    • 2 years ago
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    there is a common principle that when a body is thrown up from a certain height,then when it comes back to the same height, it will have the same velocity

  4. salini
    • 2 years ago
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    |dw:1328876734968:dw||dw:1328876550335:dw| sincew the magnitude of velocity is same however when u see the angle made with the horizontal,first it is theta and next it is 189-theta

  5. salini
    • 2 years ago
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    sorry 180-theta*

  6. King
    • 2 years ago
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    ya so ?

  7. salini
    • 2 years ago
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    wat is your doubt in this?

  8. King
    • 2 years ago
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    i dont understand wat is the answer and hw u got it?....i only understood the same velocity thing

  9. King
    • 2 years ago
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    and also in the website there are numerical answers but we didn't get any?

  10. King
    • 2 years ago
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    and can u pls xplain with numerics b'cuz i hate variables in physics and dont understand it

  11. salini
    • 2 years ago
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    |dw:1328877186942:dw| is the question like this or are the bat and ball at the same level?

  12. King
    • 2 years ago
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    no its a parabola same height

  13. King
    • 2 years ago
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    |dw:1328877374070:dw|

  14. salini
    • 2 years ago
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    ok now first draw the diagram with all velocities, distance marked in it with wat u understood

  15. King
    • 2 years ago
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    |dw:1328877495107:dw|

  16. salini
    • 2 years ago
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    in A portion,they ask for angle made with horizontal which is 30 as i explained and the magnitude of velocity is same 20m/s dont bother about the direction being different as when we say that a vector has magnitude and direction, we mean to say that we can write it in terms of i^ j^ k^ anyway my magnitude of velocity remains the same if u want to write that velocity in terms of components i can teach u how to do it the u get a solid vector notation of the velocity when ball leaves bat

  17. King
    • 2 years ago
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    ok...can u teach me hw to write in terms of components?

  18. salini
    • 2 years ago
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    |dw:1328877872806:dw| give me the values for vx and vy

  19. King
    • 2 years ago
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    vy=2cos30 or 20cos30?

  20. King
    • 2 years ago
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    salini?

  21. salini
    • 2 years ago
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    value

  22. King
    • 2 years ago
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    is it 2cos30 or 20cos30 i cant understand..if u tell me that i will calculate the value

  23. salini
    • 2 years ago
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    20*root3/2 and 20*1/2

  24. King
    • 2 years ago
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    i meant it looked like 2cos30

  25. King
    • 2 years ago
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    it is 10sqrt3 and 10

  26. salini
    • 2 years ago
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    |dw:1328878380008:dw|where i and j are direction along x and y axis and are mutually perpendicular to one another

  27. King
    • 2 years ago
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    do u hav to use i cap and j cap?

  28. salini
    • 2 years ago
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    AND THATS HOW U REPRESENT ANY VECTOR YES U HAVE TO TO SPECIFY DIRECTIONS

  29. King
    • 2 years ago
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    hey why u gettin angry?i am not ud at those and we hav to find only magnitude anyways..if u are irritated and dont wanna explain its fine

  30. King
    • 2 years ago
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    *gud

  31. salini
    • 2 years ago
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    no I turned the capslock when i answered arvind

  32. King
    • 2 years ago
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    oh!sry!

  33. King
    • 2 years ago
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    sry salini i shall try frm here on my own...rite nw i gtg!

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