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\[(1+2x)/(1-2x)\]

Oh. Need to go up too and including the term \[x ^{2}\]

so its x^2+2x+1/1-2x?

Could you explain the steps? thank you very much for your timee!

Is that \[(1+2x) \times (1-2x)\] or \[\frac{(1+2x)}{(1-2x)}\]?

Okay give me a minute to work this out :)

If it is any help the answer is \[(1+2x)(1+2x+4x ^{2})\]

(1+2x) over (1-2x) can never be equal to (1+2x)(1+2x+4x²)
and you can assure that by substitution.

either the answer is wrong or you forgot something when posting the problem
i agree with y2o2

http://mathworld.wolfram.com/NegativeBinomialSeries.html

Yes they only had to do the terms until it reaches x^2 power

ok thanks for clearing it up :)

Thank you very much guys! Clears things up!