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anonymous
 4 years ago
Need to use the binomal therom to expand (1+2x)/(12x) Not sure where to start to get it into the right format.
anonymous
 4 years ago
Need to use the binomal therom to expand (1+2x)/(12x) Not sure where to start to get it into the right format.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh. Need to go up too and including the term \[x ^{2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Could you explain the steps? thank you very much for your timee!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is that \[(1+2x) \times (12x)\] or \[\frac{(1+2x)}{(12x)}\]?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I have been trying to do those Fractions but am unable to do it! Soo fustrating! Yes it is the the (1+2x) over (12x)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay give me a minute to work this out :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If it is any help the answer is \[(1+2x)(1+2x+4x ^{2})\]

y2o2
 4 years ago
Best ResponseYou've already chosen the best response.1(1+2x) over (12x) can never be equal to (1+2x)(1+2x+4x²) and you can assure that by substitution.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[(1+2x)(12x)^{1}=(1+2x)(1^{1}+1*1^{11}*2x+\frac{1(11)}{2} (1)^{12}(2x)^2+...)\]\[=(1+2x)(1^{1}+2x+\frac{1(2)}{2} (1)^{3}*4x^2+...)\]\[=(1+2x)(1+2x+\frac{2}{2} *1*4x^2+...)\]\[=(1+2x)(1+2x+4x^2+...)\] This is from this rule \[(a+b)^n=a^n+na^{n1}b+\frac{n(n1)}{2}a^{n2}b^2+....\] Sorry it took so long :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0either the answer is wrong or you forgot something when posting the problem i agree with y2o2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@zed yes it becomes an infinite sum..is that the solution they are looking for? their answer stops after 4x^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes they only had to do the terms until it reaches x^2 power

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok thanks for clearing it up :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you very much guys! Clears things up!
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