## anonymous 4 years ago find the domain and range of f(x)=1+x(square)

1. ash2326

$f(x)=1+x^2$ as there is no x for which f(x) is undefined domain= all real numbers the minimum value of f(x)= 1 when x=0 so range = [1, $$\infty$$) or f(x)>=1

2. perl

domain: all reals range : [1 , oo)

3. perl

ash, good explanation ;)

4. perl

we take as the domain the largest possible set of real numbers. since there are no restrictions (no points that are undefined), the domain is all reals

5. perl

, it is assumed that the domain is the largest possible set of reals

6. ash2326

izzati you got it?

7. anonymous

actually i dont understand...it is in exam we should write it like that??

8. ash2326

yeah izzati

9. anonymous

how you got the range..explain plez..

10. ash2326

We have $f(x)=1+x^2$ we know that x^2 's minimum value is 0 whether x>0 or x<0 , value of square of x will be greater than 0 so its minimum value is 0 so f(x)'s minimum value is 1+0=1 when x^2 increases, f(x) also increases when x -----> infinity , f(x) ----> infinity no maximum limit of f(x) so f(x) 's range is greater than or equal to 1 f(x)>=1 or range is [1, $$\infty$$)

11. anonymous

ok.i got it thanx