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anonymous
 4 years ago
find the domain and range of f(x)=1+x(square)
anonymous
 4 years ago
find the domain and range of f(x)=1+x(square)

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ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2\[f(x)=1+x^2\] as there is no x for which f(x) is undefined domain= all real numbers the minimum value of f(x)= 1 when x=0 so range = [1, \(\infty\)) or f(x)>=1

perl
 4 years ago
Best ResponseYou've already chosen the best response.1domain: all reals range : [1 , oo)

perl
 4 years ago
Best ResponseYou've already chosen the best response.1we take as the domain the largest possible set of real numbers. since there are no restrictions (no points that are undefined), the domain is all reals

perl
 4 years ago
Best ResponseYou've already chosen the best response.1, it is assumed that the domain is the largest possible set of reals

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0actually i dont understand...it is in exam we should write it like that??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how you got the range..explain plez..

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2We have \[f(x)=1+x^2\] we know that x^2 's minimum value is 0 whether x>0 or x<0 , value of square of x will be greater than 0 so its minimum value is 0 so f(x)'s minimum value is 1+0=1 when x^2 increases, f(x) also increases when x > infinity , f(x) > infinity no maximum limit of f(x) so f(x) 's range is greater than or equal to 1 f(x)>=1 or range is [1, \(\infty\))
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