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AravindG
 4 years ago
what is head on collision?
AravindG
 4 years ago
what is head on collision?

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ash2326
 4 years ago
Best ResponseYou've already chosen the best response.3Both the bodies approaching towards each other and collide.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Usually, this means the angle between the two velocity vectors of the two moving objects is zero. This is still pretty ambiguous.

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.1hmm. is there any condition i??like referring to centre of mass and all?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That is another consideration. Like I said, this is ambiguous. We could define the velocity vectors are being parallel and the center of masses to be colinear. The line containing both center of masses should also be parallel to the velocities.

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1327850906578:dw are both a and B head on collision?

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.3http://hyperphysics.phyastr.gsu.edu/hbase/colsta.html I think so

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.1well i hav a figure can u xplain it ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0They could be depending on the definition. Again, this is ambiguous. We need to first define a head on collision before we can identify one. Typically the "head" of an object is that that is furthest from the center of mass in the direction of the velocity. Think of a nose on an airplane as being the "head."

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I would say that only B is a "head on" collision.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No. Because we haven't adequately defined head on collision! LISTEN!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0There is no formal definition as far as I can tell. We need to define it here for the context of this problem.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Center of masses  Colinear. Velocities  parallel, colinear, line containing center of mass contains vectors defining velocities. We need to decide is the relative velocities matters. That is, for a collision to be headon, should the objects be travelling towards each other? Can one be at rest? Can they be travelling in the same direction?

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.1ya thats wat i am asking u asking dis to me lol :)

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.1accordind to ur definition if velocities are parallel the bodies wont move towards each other!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0They can be parallel and have opposite signs.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I would not consider two objects travelling in the same direction as being a "headon" collision. Instead it would be a "head to tail" collision.

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0the meaning of head on collision that I have come across always indicates a collision of two bodies "heading towards one another". i.e. "B" in your diagram above. "A" in your diagram above is usually referred to as a "rearend collision". But I cannot be certain if these are the "true" definitions of the terms.

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.1k i got it now can u guys xplain to me what is said in that diagram above??it is about a motion of ball bouncing and eventually reaching reat can u say hw we got those eqns like e^2h

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Please post that question as a separate post, with adequate explanation.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0As a separate question. Not here.
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