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anonymous
 4 years ago
How do I know when to use M=u*(r X F) or M= r X F to find the Momentum
anonymous
 4 years ago
How do I know when to use M=u*(r X F) or M= r X F to find the Momentum

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is that u times (r cross F) or is X a variable?\[M = u \cdot (r \times F) ~~ {\rm or}~~ M = u \cdot (r \cdot X \cdot F)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0u dot product ( r cross product F)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay. Another question: What quantity is u? I want to make sure we are on the same page here. I have a feeling we are defining angular momentum here and not translation momentum.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I know how to do it because the book shows it using the cartesian values but my question is when a problem is given to find M , how do I know if I use M=u*(r X F) or just M = r X F

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I got it. You are looking to calculate the moment not momentum. I would always use\[M = r \times F\]I don't know what u represents. If I know what it is, I can advise you on how to use it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0In the example you have given, to find the moment about point A, using the following expression. \[M_A = [0.6 \hat i + 0.3 \hat k] \times [300 \hat k] = (0.6 \cdot 300) \cdot [\hat i \times \hat k] + (0.3 \cdot 300) \cdot [\hat k \times \hat k] = (0.6 \cdot 300) \hat j\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[M_A = (0.6 \cdot 300) \hat j\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0beccause the problem says find the Mab produced by the Force

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0To find the moment about point B, \[M_B = [0.2 \hat i  0.2 \hat j + 0.3 \hat k] \times 300 \hat k\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0For a moment about the line through A and B, \[M_{AB} = \vec u_{A/B} \cdot (\vec r_o \times F_C)\]where \(\vec r_o\) is the vector from any point of the segment AB to C.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0We use the vector \(\vec u_{A/B}\) when we are finding the moment about a line or axis. We use the regular cross product when we are finding the moment about a point.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[M_{line} = \vec u \cdot (r_o \times F)\]\[M_{point} = r \times F\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Perfect!!!!! Thank you soooooo much!!! Couldn't be explained better!!!!
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