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anonymous
 4 years ago
find d^2y/dx^2 for y=(1x)/(2x)
anonymous
 4 years ago
find d^2y/dx^2 for y=(1x)/(2x)

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amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0find the second derivative ... right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0try the quotient rule

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0then i would either use a product rule with a ^1; or the quotient rule

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0youd have to do it twice tho to get to the second one

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{t}{b}=tb^{1}\] \[D_x[tb^{1}]=tb^{2}+t'b^{1}\] \[D_{x}^{2}[tb^{1}]=D_x[tb^{2}+t'b^{1}]\] \[D_x[tb^{2}+b^{1}]=2tb^{3}t'b^{2}t'b^{2}+t''b^{1}\] witha any luck I kept it all in order lol

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0t=(1x) t' = 1 t'' = 0 b=(2x) \[2(1x)(2x)^{3}+(2x)^{2}+(2x)^{2}+0(b^{1})\] \[2(1x)(2x)^{3}+2(2x)^{2}\] \[2(2x)^{3}\left((1x)+(2x)\right)\] \[\frac{2(3)}{(2x)^{3}}\] the wolf should be able to check that tho

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0almost kept it straight :) http://www.wolframalpha.com/input/?i=second+derivative+t%28x%29%28b%28x%29%29%5E%281%29 2  (x2)^3 http://www.wolframalpha.com/input/?i=second+derivative+%281x%29%2F%282x%29
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