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anonymous
 4 years ago
solve for x
1. x^5=31
2. x^4/3=64
3. 27^2/3=x^1/2
anonymous
 4 years ago
solve for x 1. x^5=31 2. x^4/3=64 3. 27^2/3=x^1/2

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0calculator for this one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0unless you mean \[x^5=32\] in which case \[x=2\] because \[2^5=32\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.027^(2/3) is the same as 3^2 is the same as 9 .. so 9 is left side of equation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so 9=x^(1/2) square both sides to find x x=81 ..............ans.3.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for the first one: x=31^(1/5).............ans1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and for the second one first take the cube root of 64=4 then raise it to the power of 4 which is 256 x=256

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait i think i did the second one wrong! however, there is something wrong with the question

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well, that's what the teacher has on the paper, __"

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you have to first take the 4th root of 64 and you can't take an even root of a negative number

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0unless you are dealing with complex numbers.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, not likely something raised to the fourth power will be negative
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