anonymous
  • anonymous
what would this be (sq rt 0f 21) * (sq rt 0f 3)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Do like the last problem and multiply the two numbers under the root together and then find any perfect squares.
anonymous
  • anonymous
how there are no perfect roots there is 7 and 3 put neight of those are perfect squaer
anonymous
  • anonymous
There is 7*3=21 and 3 so your factors are 7,3,3.... because the problem is \[\sqrt{21*3}\]

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anonymous
  • anonymous
both problems have the same root so you can multiply the numbers under the root together.
anonymous
  • anonymous
im still not getting this
anonymous
  • anonymous
What do you get if you multiply 21*3? Then what are the factors of that? Then take out any factor pairs and what is left is what stays under the square root.
anonymous
  • anonymous
63
anonymous
  • anonymous
1and63 3and 21 9and 7 so i would use this one
anonymous
  • anonymous
Right, because 9 is a perfect square and 7 doesn't have any perfect square factors.
anonymous
  • anonymous
then what do i do with the other half of the problem
anonymous
  • anonymous
umm what other half.... the problem was \[\sqrt{21}*\sqrt{3}\] correct?
anonymous
  • anonymous
Read my second post.
anonymous
  • anonymous
ya but what do i do with the (sq rt of 3)

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