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anonymous

  • 4 years ago

what would this be (sq rt 0f 21) * (sq rt 0f 3)

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  1. anonymous
    • 4 years ago
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    Do like the last problem and multiply the two numbers under the root together and then find any perfect squares.

  2. anonymous
    • 4 years ago
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    how there are no perfect roots there is 7 and 3 put neight of those are perfect squaer

  3. anonymous
    • 4 years ago
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    There is 7*3=21 and 3 so your factors are 7,3,3.... because the problem is \[\sqrt{21*3}\]

  4. anonymous
    • 4 years ago
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    both problems have the same root so you can multiply the numbers under the root together.

  5. anonymous
    • 4 years ago
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    im still not getting this

  6. anonymous
    • 4 years ago
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    What do you get if you multiply 21*3? Then what are the factors of that? Then take out any factor pairs and what is left is what stays under the square root.

  7. anonymous
    • 4 years ago
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    63

  8. anonymous
    • 4 years ago
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    1and63 3and 21 9and 7 so i would use this one

  9. anonymous
    • 4 years ago
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    Right, because 9 is a perfect square and 7 doesn't have any perfect square factors.

  10. anonymous
    • 4 years ago
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    then what do i do with the other half of the problem

  11. anonymous
    • 4 years ago
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    umm what other half.... the problem was \[\sqrt{21}*\sqrt{3}\] correct?

  12. anonymous
    • 4 years ago
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    Read my second post.

  13. anonymous
    • 4 years ago
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    ya but what do i do with the (sq rt of 3)

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