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anonymous
 4 years ago
A 4.20 m diameter merrygoround is rotating freely with angular speed of 0.800 rad/s. Its total moment of inertia is 1260 kg m squared. How much work will bring the merrygoround to rest?
anonymous
 4 years ago
A 4.20 m diameter merrygoround is rotating freely with angular speed of 0.800 rad/s. Its total moment of inertia is 1260 kg m squared. How much work will bring the merrygoround to rest?

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JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.1The rotational kinetic energy of the merrygoround is \[ KE_r = \frac{1}{2}I\omega^2 \] Now, you want to reduce that to zero. Hence by the workenergy theorem, you need to do exactly an equal amount of work.

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.1make sense? It's analogous to asking "How much work is required to stop a 1000 kg car moving at 10 m/s?" We need to do \[ KE = \frac{1}{2}mv^2 \] of work.
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