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anonymous

  • 4 years ago

Given the triangle below, what is cot∡B?

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  1. anonymous
    • 4 years ago
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    Please give the triangle :D

  2. anonymous
    • 4 years ago
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  3. anonymous
    • 4 years ago
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    A) square root of 33 over 7 B) 7 times square root of 33 over 33 C) 4 times square root of 33 over 33 D) square root of 33 over 4

  4. anonymous
    • 4 years ago
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    It is D) Square root of 33 over 4.

  5. anonymous
    • 4 years ago
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    okay I have one more question!

  6. anonymous
    • 4 years ago
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    Shoot

  7. anonymous
    • 4 years ago
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    what is the value of x?

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  8. anonymous
    • 4 years ago
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    Can't see x in the given figure.

  9. phi
    • 4 years ago
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    this is a multi-step problem. First, you need to know that cot B = 1/tan B so if we can find tan B, we flip it to get cot B tan B = opposite/adjacent opposite=4 adjacent= ? to find adjacent we use pythagoras: a^2 + b^2 = c^2 here a=? , b=4, c=7, so: a^2 + 16= 49 and a^2= 49-16= 33 so a= sqrt(33) putting it together: tan B= 4/sqrt(33), and cot B= sqrt(33)/4

  10. anonymous
    • 4 years ago
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    sec∠C - cot∠A = 3x A) fraction 7 minus square root of 13 over 18 B) square root of 13 over 3 C) fraction square root of 13 over 3 D) fraction 6 minus square root of 13 over 7

  11. phi
    • 4 years ago
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    First, can you find the length of side AB?

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