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anonymous
 4 years ago
How do I solve z^2+(3+4i)z1+5i=0
anonymous
 4 years ago
How do I solve z^2+(3+4i)z1+5i=0

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TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1just use the quadratic formula the only tricky part is taking the square root...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how can you show me? please

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[z=\frac{(3+4i)\pm\sqrt{(3+4i)^24(1+5i)}}2\]\[=\frac{(3+4i)\pm\sqrt{9+24i16+420i)}}2\]\[=\frac{(3+4i)\pm\sqrt{3+4i}}2\]the technique for the square root here is long winded, but I just considered that the the numbers must foil out to that expression and saw that \[\sqrt{3+4i}=1+2i\]because\[(1+2i)(1+2i)=3+4i\]is that at all obvious to you? or do you want to see the whole procedure?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1so you get\[z=\frac{(3+4i)\pm(1+2i)}2=\left\{ 23i,1i \right\}\]as a final answer
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