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anonymous

  • 4 years ago

Alan leaves Los Angeles at 8:00 a.m. to drive to San Francisco, 400 away. He travels at a steady 45.0 . Beth leaves Los Angeles at 9:00 a.m. and drives a steady 57.0. How long does the first have to wait for the second?

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  1. anonymous
    • 4 years ago
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    Assuming that Beth gets there first

  2. TuringTest
    • 4 years ago
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    you don't have to assume anything velocity is distance over time:\[v=\frac dt\]so time can be found from distance and velocity\[t=\frac dv\]for the Alan the time of travel is is\[t_A=\frac d{v_A}\]and for Beth the time taken is\[t_B=\frac d{v_B}+1\](the +1 is for the extra hour she waits to depart) all we need is the difference of the times\[\Delta t=t_A-t_B\]and that will tell us how long they waited.

  3. anonymous
    • 4 years ago
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    So Beth waited 53 minutes... Thanks for the help :)

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