## anonymous 4 years ago Alan leaves Los Angeles at 8:00 a.m. to drive to San Francisco, 400 away. He travels at a steady 45.0 . Beth leaves Los Angeles at 9:00 a.m. and drives a steady 57.0. How long does the first have to wait for the second?

1. anonymous

Assuming that Beth gets there first

2. TuringTest

you don't have to assume anything velocity is distance over time:$v=\frac dt$so time can be found from distance and velocity$t=\frac dv$for the Alan the time of travel is is$t_A=\frac d{v_A}$and for Beth the time taken is$t_B=\frac d{v_B}+1$(the +1 is for the extra hour she waits to depart) all we need is the difference of the times$\Delta t=t_A-t_B$and that will tell us how long they waited.

3. anonymous

So Beth waited 53 minutes... Thanks for the help :)

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