• anonymous
Alan leaves Los Angeles at 8:00 a.m. to drive to San Francisco, 400 away. He travels at a steady 45.0 . Beth leaves Los Angeles at 9:00 a.m. and drives a steady 57.0. How long does the first have to wait for the second?
  • Stacey Warren - Expert
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
  • katieb
I got my questions answered at in under 10 minutes. Go to now for free help!
  • anonymous
Assuming that Beth gets there first
  • TuringTest
you don't have to assume anything velocity is distance over time:\[v=\frac dt\]so time can be found from distance and velocity\[t=\frac dv\]for the Alan the time of travel is is\[t_A=\frac d{v_A}\]and for Beth the time taken is\[t_B=\frac d{v_B}+1\](the +1 is for the extra hour she waits to depart) all we need is the difference of the times\[\Delta t=t_A-t_B\]and that will tell us how long they waited.
  • anonymous
So Beth waited 53 minutes... Thanks for the help :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.