anonymous
  • anonymous
What is the derivative of g(x) = 1/ sqrt (x) ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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bahrom7893
  • bahrom7893
g(x) = x^(-1/2) g'(x) = (-1/2)*x^(-3/2)
bahrom7893
  • bahrom7893
g'(x) = -1/(2*x^(3/2))
anonymous
  • anonymous
can you show me how u get this answer..i got - 1 /x as the answer..

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bahrom7893
  • bahrom7893
1/sqrt(x) = x^(-1/2) right?
anonymous
  • anonymous
yes but i left it as square root because sqrt x and sqrt x will be x
bahrom7893
  • bahrom7893
why are you multiplying this by the square root?
anonymous
  • anonymous
1/ sqrt (x+h) - 1/ sqrt (x) x 1/h = sqrt x - sqrt (x+h) / (sqrt (x+h) (sqrt x) and then multiply by the conjugate which is sqrt x + sqrt x+h
anonymous
  • anonymous
so here all the square roots will be cancelled out
bahrom7893
  • bahrom7893
oh wait u're solving this using a limit definition?
anonymous
  • anonymous
yes
anonymous
  • anonymous
then how u do it with limit?

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