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anonymous

  • 4 years ago

calculus help

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  1. bahrom7893
    • 4 years ago
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    calculus is here!

  2. anonymous
    • 4 years ago
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    Post the problem!!

  3. anonymous
    • 4 years ago
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    \[\int\limits_{?}^{?}(\cos ^{2}x-\cos ^{2}x)/(\sin x)dx\]

  4. anonymous
    • 4 years ago
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    opps the first cos is suppouse to be a sin

  5. bahrom7893
    • 4 years ago
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    Cos^2 - Sin^2?

  6. bahrom7893
    • 4 years ago
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    oh lol sorry it's the other way around

  7. anonymous
    • 4 years ago
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    \[\int\limits_{?}^{?}(\sin ^{2}x-\cos ^{2}x)/(\sin x)\]

  8. anonymous
    • 4 years ago
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    thats the problem

  9. anonymous
    • 4 years ago
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    You already asked this question. :| I didn't answer it, but you didn't reply to the old thread.

  10. anonymous
    • 4 years ago
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    i was waiting on you

  11. anonymous
    • 4 years ago
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    @badreferences

  12. anonymous
    • 4 years ago
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    I was giving you hint-by-hint. I realized just giving people answers would have them not learn anything.

  13. bahrom7893
    • 4 years ago
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    Just divide by sin Sinx - Cosx*Cotx

  14. anonymous
    • 4 years ago
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    Exactly what I said before. >.> Also, cosxcotx can be expressed as cscx-sinx.

  15. bahrom7893
    • 4 years ago
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    all right continue badrefs, finish ur answer!

  16. anonymous
    • 4 years ago
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    i am getting stuck on how you integrate that

  17. anonymous
    • 4 years ago
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    The integral of sinx is -cosx, riiight? The integral of cscx is -ln(sin(x/2))-ln(cos(x/2)). TBH, though, I forget how you prove that last part. It's just something I committed to memory and WolframAlpha lol.

  18. anonymous
    • 4 years ago
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    But like trig integrals, it's just something I remembered. So...

  19. anonymous
    • 4 years ago
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    ok thanks dude

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