anonymous
  • anonymous
calculus help
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
bahrom7893
  • bahrom7893
calculus is here!
anonymous
  • anonymous
Post the problem!!
anonymous
  • anonymous
\[\int\limits_{?}^{?}(\cos ^{2}x-\cos ^{2}x)/(\sin x)dx\]

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anonymous
  • anonymous
opps the first cos is suppouse to be a sin
bahrom7893
  • bahrom7893
Cos^2 - Sin^2?
bahrom7893
  • bahrom7893
oh lol sorry it's the other way around
anonymous
  • anonymous
\[\int\limits_{?}^{?}(\sin ^{2}x-\cos ^{2}x)/(\sin x)\]
anonymous
  • anonymous
thats the problem
anonymous
  • anonymous
You already asked this question. :| I didn't answer it, but you didn't reply to the old thread.
anonymous
  • anonymous
i was waiting on you
anonymous
  • anonymous
@badreferences
anonymous
  • anonymous
I was giving you hint-by-hint. I realized just giving people answers would have them not learn anything.
bahrom7893
  • bahrom7893
Just divide by sin Sinx - Cosx*Cotx
anonymous
  • anonymous
Exactly what I said before. >.> Also, cosxcotx can be expressed as cscx-sinx.
bahrom7893
  • bahrom7893
all right continue badrefs, finish ur answer!
anonymous
  • anonymous
i am getting stuck on how you integrate that
anonymous
  • anonymous
The integral of sinx is -cosx, riiight? The integral of cscx is -ln(sin(x/2))-ln(cos(x/2)). TBH, though, I forget how you prove that last part. It's just something I committed to memory and WolframAlpha lol.
anonymous
  • anonymous
But like trig integrals, it's just something I remembered. So...
anonymous
  • anonymous
ok thanks dude

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