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anonymous
 4 years ago
calculus help
anonymous
 4 years ago
calculus help

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{?}^{?}(\cos ^{2}x\cos ^{2}x)/(\sin x)dx\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0opps the first cos is suppouse to be a sin

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.0oh lol sorry it's the other way around

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{?}^{?}(\sin ^{2}x\cos ^{2}x)/(\sin x)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You already asked this question. : I didn't answer it, but you didn't reply to the old thread.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I was giving you hintbyhint. I realized just giving people answers would have them not learn anything.

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.0Just divide by sin Sinx  Cosx*Cotx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Exactly what I said before. >.> Also, cosxcotx can be expressed as cscxsinx.

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.0all right continue badrefs, finish ur answer!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i am getting stuck on how you integrate that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The integral of sinx is cosx, riiight? The integral of cscx is ln(sin(x/2))ln(cos(x/2)). TBH, though, I forget how you prove that last part. It's just something I committed to memory and WolframAlpha lol.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But like trig integrals, it's just something I remembered. So...
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