cathyangs
  • cathyangs
Disprove this proof of the statement 2=1 a=b a^2=ab a^2-b^2=ab-b^2 (a-b)(a+b)=b(a-b) ((a-b)(a+b))/(a-b)=(b(a-b))/(a-b) a+b=b b+b=b 2b=b 2=1
Mathematics
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cathyangs
  • cathyangs
Disprove this proof of the statement 2=1 a=b a^2=ab a^2-b^2=ab-b^2 (a-b)(a+b)=b(a-b) ((a-b)(a+b))/(a-b)=(b(a-b))/(a-b) a+b=b b+b=b 2b=b 2=1
Mathematics
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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nenadmatematika
  • nenadmatematika
when you divide with (a-b) in the fifth line, you must know that it's only possible when a is not equal to b, otherwise you will get dividing by zero which is not possible....so you can't divide by a-b because your condition in the first line is a=b
cathyangs
  • cathyangs
nice catch! :D I gave this to my dad (a "Permanent-head-damage") and he laughed when he saw it.

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