• anonymous
A rock is tossed straight up with a velocity of When it returns, it falls into a hole deep. What is the velocity as it hits the bottom of the hole?
  • Stacey Warren - Expert
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  • schrodinger
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  • anonymous
Alright, let's say the rock is tossed up with an initial velocity of x. There is a downwards acceleration of -9.8ms^-2. I assume no air resistance. Let's say it falls into a hole L deep. Let's also say the rock is thrown from ground level, since you're not giving me any information. x-x_0=v_0t+0.5gt^2 L=xt+0.5(-9.8)t^2 Solve for t. Once you find t, which should be a simple application of the quadratic formula, plug that t in for v=v_0+at, or v=x+(-9.8)t. There. I can't give you any numbers, since you didn't give me any.

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