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anonymous

  • 4 years ago

What is the derivative of g(x) = 1/ sqrt (x) using limit?

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  1. bahrom7893
    • 4 years ago
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    (1/(sqrt(x+h)))-(1/sqrt(x)))/h

  2. bahrom7893
    • 4 years ago
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    h->0

  3. bahrom7893
    • 4 years ago
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    |dw:1328833506404:dw|

  4. bahrom7893
    • 4 years ago
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    |dw:1328833576708:dw|

  5. bahrom7893
    • 4 years ago
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    |dw:1328833639546:dw|

  6. bahrom7893
    • 4 years ago
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    |dw:1328833700228:dw|

  7. bahrom7893
    • 4 years ago
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    |dw:1328833740275:dw|

  8. bahrom7893
    • 4 years ago
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    all right that's it.

  9. anonymous
    • 4 years ago
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    h is not negative?? (sqrt x) - (sqrt (x+h)) is there no brackets around them?

  10. bahrom7893
    • 4 years ago
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    h is not negative where?

  11. anonymous
    • 4 years ago
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    x - x + h < is h not -ve here?

  12. bahrom7893
    • 4 years ago
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    no it's under square root, so the signs of h are preserved

  13. anonymous
    • 4 years ago
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    and can u explain how you you multiply sqrt (x(x+h) and sqrt x + sqrt (x+h) together..?? how u get sqrt x + sqrt (x+h) from that.. thanks so much

  14. bahrom7893
    • 4 years ago
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    it's the form a^2-b^2, where a=sqrt(x), b=sqrt(x+h)

  15. bahrom7893
    • 4 years ago
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    so we basically had a-b, so i multiplied both sides by a+b, to get it into form a^2-b^2

  16. bahrom7893
    • 4 years ago
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    to get rid of the sqrt

  17. anonymous
    • 4 years ago
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    ohh ok ok i get it thank you u square both sides right?

  18. bahrom7893
    • 4 years ago
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    well yea technically, but squaring won't work so I multiplied by a+b

  19. anonymous
    • 4 years ago
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    oh ok thanks!!

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