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anonymous
 4 years ago
A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 12 square feet. Find the lengths of the sides of the poster and the sign
anonymous
 4 years ago
A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 12 square feet. Find the lengths of the sides of the poster and the sign

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's easy! what is the formula for a square?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I won't be able to help you if you will just be silent!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I got 16ft for the sign and 4 ft for the poster does that seem correct to you?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0does it match yours>?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, let's see! a ( is a poster ) and b ( sign) Area = a^2 Area = b^2 b^2  a^2 = 12 if a = b 2 we just plug it in our formula! b^2  (b2)^2 = 12 b^2  b^2 + 4b  4 = 12 4b  4 = 12 4b = 16 b = 4 Area for b = 16 Area for a = 4 You are correct :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yay thanks for checking with me hugs
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