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when x goes to zero y approaches 8

yea i am trying to determine what the graph would look like

But I am thy Master Chief?
http://www.wolframalpha.com/input/?i=y%3D.5x%2B8

it's 1/x not (1/2)x there chief

well it 1/(x+8)

but (x-8) is different from x+8 when graphing

you know anyone can type numbers in to wolfram

(x+8) oops

i'm talking to chief

yea i want to know how to graph the thing

Well of course, although I could rule the Earth if it was off limits to everyone but me...

i can go to a graphing calculator and not come here but it doesnt teach me how to graph it

i disagree chief. conversation over.

So i assume that I would substitute random numbers for X to graph it?

so if x= 0 y would = 1/8

Umm, Well, you put 0 in for x. This cancels out the numerator of 1 above it. The answer would be 8.

Because 1 divided 0 is nothing, 0.

1/(x+8)

i cant figure out how to put the one over both in here

in the original problem there is no parenthesis

Oh, that's a different story. Yes, it would com eout as \[1/8\]

because x+8 and (x+8) would be different shifts when graphing wouldnt it?

Yes, the solution graph would differ.

one would shift the graph up and one would shift the graph left

so i am assuming there would be a hole in my graph at -8

because -8+8 = 0

I entered the two equations.

the first one is correct. Thats where I was confused

because at x=-9

Yes, it does move the graph to the right if you seclude the +8

the equation would result in a negative

hence a verticle asymtope at -8

x can never be -8 )

you did great, and you helped me answer a college calculus question

just remember that the denominator can never = 0 so if it does you have a hole

hence for 1/(-8+8)

=1/0

Oh wow, Thank you!
And yes, because you can't have, for instance, 4 slices of nothing, right?

the value doesnt exist

Like, 4/0

so in your graph that spot would be left open

it doesnt exist

Yes, I know what you mean. It's like trying to have one piece of nothing. That doesn't exist!

I understand now.

so in this case we have an asymptope which means we can get closer and closer to 8

Yup, I get it now thanks!

such as 7.999

so the graph goes up and down at 8 infinitely

I think so.