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ChrisV

graph the fuction f(x)= 1/x+8

  • 2 years ago
  • 2 years ago

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  1. mattt9
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    when x goes to zero y approaches 8

    • 2 years ago
  2. ChrisV
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    yea i am trying to determine what the graph would look like

    • 2 years ago
  3. MasterChief
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    But I am thy Master Chief? http://www.wolframalpha.com/input/?i=y%3D.5x%2B8

    • 2 years ago
  4. mattt9
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    it's 1/x not (1/2)x there chief

    • 2 years ago
  5. ChrisV
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    well it 1/(x+8)

    • 2 years ago
  6. MasterChief
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    Preposterous! How could I have made such a delinquent mistake? http://www.wolframalpha.com/input/?i=y%3D%281%2Fx%29%2B8

    • 2 years ago
  7. ChrisV
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    but (x-8) is different from x+8 when graphing

    • 2 years ago
  8. mattt9
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    you know anyone can type numbers in to wolfram

    • 2 years ago
  9. ChrisV
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    (x+8) oops

    • 2 years ago
  10. mattt9
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    i'm talking to chief

    • 2 years ago
  11. ChrisV
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    yea i want to know how to graph the thing

    • 2 years ago
  12. MasterChief
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    Well of course, although I could rule the Earth if it was off limits to everyone but me...

    • 2 years ago
  13. ChrisV
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    i can go to a graphing calculator and not come here but it doesnt teach me how to graph it

    • 2 years ago
  14. mattt9
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    i disagree chief. conversation over.

    • 2 years ago
  15. ChrisV
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    So i assume that I would substitute random numbers for X to graph it?

    • 2 years ago
  16. MasterChief
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    Make a table and input numbers for x like 0, and then see what comes out as y. Keep getting numbers until you can make a decent graph.

    • 2 years ago
  17. ChrisV
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    so if x= 0 y would = 1/8

    • 2 years ago
  18. MasterChief
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    Disagree with what? Obviously, no s**t anyone can use it! I linked a page to the graph, to make things easier even though I misunderstood the question.

    • 2 years ago
  19. MasterChief
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    Umm, Well, you put 0 in for x. This cancels out the numerator of 1 above it. The answer would be 8.

    • 2 years ago
  20. MasterChief
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    Because 1 divided 0 is nothing, 0.

    • 2 years ago
  21. ChrisV
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    1/(x+8)

    • 2 years ago
  22. ChrisV
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    i cant figure out how to put the one over both in here

    • 2 years ago
  23. ChrisV
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    in the original problem there is no parenthesis

    • 2 years ago
  24. MasterChief
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    Oh, that's a different story. Yes, it would com eout as \[1/8\]

    • 2 years ago
  25. ChrisV
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    because x+8 and (x+8) would be different shifts when graphing wouldnt it?

    • 2 years ago
  26. MasterChief
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    Yes, the solution graph would differ.

    • 2 years ago
  27. ChrisV
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    one would shift the graph up and one would shift the graph left

    • 2 years ago
  28. ChrisV
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    so i am assuming there would be a hole in my graph at -8

    • 2 years ago
  29. ChrisV
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    because -8+8 = 0

    • 2 years ago
  30. MasterChief
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    Sorry, it appears so. I have not taken this but look: http://www.wolframalpha.com/input/?i=y%3D1%2F%28x%2B8%29%2C+y%3D%281%2Fx%29%2B8

    • 2 years ago
  31. MasterChief
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    I entered the two equations.

    • 2 years ago
  32. ChrisV
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    the first one is correct. Thats where I was confused

    • 2 years ago
  33. ChrisV
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    because at x=-9

    • 2 years ago
  34. MasterChief
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    Yes, it does move the graph to the right if you seclude the +8

    • 2 years ago
  35. ChrisV
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    the equation would result in a negative

    • 2 years ago
  36. ChrisV
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    hence a verticle asymtope at -8

    • 2 years ago
  37. ChrisV
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    x can never be -8 )

    • 2 years ago
  38. MasterChief
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    I would love to answer your question here but I really don't know. I'm in eighth grade and enrolled in Algebra 2. Sorry!

    • 2 years ago
  39. ChrisV
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    you did great, and you helped me answer a college calculus question

    • 2 years ago
  40. ChrisV
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    just remember that the denominator can never = 0 so if it does you have a hole

    • 2 years ago
  41. ChrisV
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    hence for 1/(-8+8)

    • 2 years ago
  42. ChrisV
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    =1/0

    • 2 years ago
  43. MasterChief
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    Oh wow, Thank you! And yes, because you can't have, for instance, 4 slices of nothing, right?

    • 2 years ago
  44. ChrisV
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    the value doesnt exist

    • 2 years ago
  45. MasterChief
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    Like, 4/0

    • 2 years ago
  46. ChrisV
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    so in your graph that spot would be left open

    • 2 years ago
  47. ChrisV
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    it doesnt exist

    • 2 years ago
  48. MasterChief
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    Yes, I know what you mean. It's like trying to have one piece of nothing. That doesn't exist!

    • 2 years ago
  49. MasterChief
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    I understand now.

    • 2 years ago
  50. ChrisV
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    so in this case we have an asymptope which means we can get closer and closer to 8

    • 2 years ago
  51. MasterChief
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    Yup, I get it now thanks!

    • 2 years ago
  52. ChrisV
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    such as 7.999

    • 2 years ago
  53. ChrisV
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    so the graph goes up and down at 8 infinitely

    • 2 years ago
  54. MasterChief
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    I think so.

    • 2 years ago
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