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anonymous
 4 years ago
graph the fuction f(x)= 1/x+8
anonymous
 4 years ago
graph the fuction f(x)= 1/x+8

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0when x goes to zero y approaches 8

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea i am trying to determine what the graph would look like

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But I am thy Master Chief? http://www.wolframalpha.com/input/?i=y%3D.5x%2B8

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's 1/x not (1/2)x there chief

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Preposterous! How could I have made such a delinquent mistake? http://www.wolframalpha.com/input/?i=y%3D%281%2Fx%29%2B8

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but (x8) is different from x+8 when graphing

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you know anyone can type numbers in to wolfram

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea i want to know how to graph the thing

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well of course, although I could rule the Earth if it was off limits to everyone but me...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i can go to a graphing calculator and not come here but it doesnt teach me how to graph it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i disagree chief. conversation over.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So i assume that I would substitute random numbers for X to graph it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Make a table and input numbers for x like 0, and then see what comes out as y. Keep getting numbers until you can make a decent graph.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so if x= 0 y would = 1/8

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Disagree with what? Obviously, no s**t anyone can use it! I linked a page to the graph, to make things easier even though I misunderstood the question.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Umm, Well, you put 0 in for x. This cancels out the numerator of 1 above it. The answer would be 8.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Because 1 divided 0 is nothing, 0.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i cant figure out how to put the one over both in here

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in the original problem there is no parenthesis

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh, that's a different story. Yes, it would com eout as \[1/8\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0because x+8 and (x+8) would be different shifts when graphing wouldnt it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, the solution graph would differ.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0one would shift the graph up and one would shift the graph left

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so i am assuming there would be a hole in my graph at 8

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry, it appears so. I have not taken this but look: http://www.wolframalpha.com/input/?i=y%3D1%2F%28x%2B8%29%2C+y%3D%281%2Fx%29%2B8

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I entered the two equations.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the first one is correct. Thats where I was confused

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, it does move the graph to the right if you seclude the +8

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the equation would result in a negative

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hence a verticle asymtope at 8

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I would love to answer your question here but I really don't know. I'm in eighth grade and enrolled in Algebra 2. Sorry!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you did great, and you helped me answer a college calculus question

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just remember that the denominator can never = 0 so if it does you have a hole

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh wow, Thank you! And yes, because you can't have, for instance, 4 slices of nothing, right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the value doesnt exist

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so in your graph that spot would be left open

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, I know what you mean. It's like trying to have one piece of nothing. That doesn't exist!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so in this case we have an asymptope which means we can get closer and closer to 8

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yup, I get it now thanks!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so the graph goes up and down at 8 infinitely
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