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What is the sum of the angle measures of a 37-gon?

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35(180) a la 180(n-2)
Sum of internal angles of a polygon with no. of sides n= (n-2)*180 for a 37 gon, n= 37 so sum of angles= (37-2)*180=35*180=6300
Man, ash, way to show me up with a better answer.

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Other answers:

(180-360/37) * 37
Don't use the "formula". Use the approach of triangles and angles. :) |dw:1328837860338:dw|
do you know this Find the value of x. The diagram is not to scale.
it all has to add up to 540 degrees. So....
Ok care to explain please this is the last one I have trouble with :(
Use the same approach I showed above: You get (180-360/5)*5 = (180-72)*5 = 108*5 = 540 degrees. Sum of all five angles should be 540 degrees. So, you get an equation in x and solve for x.

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