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What is the sum of the angle measures of a 37-gon?

Mathematics
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35(180) a la 180(n-2)
Sum of internal angles of a polygon with no. of sides n= (n-2)*180 for a 37 gon, n= 37 so sum of angles= (37-2)*180=35*180=6300
Man, ash, way to show me up with a better answer.

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Other answers:

(180-360/37) * 37
Don't use the "formula". Use the approach of triangles and angles. :) |dw:1328837860338:dw|
do you know this Find the value of x. The diagram is not to scale. https://www.connexus.com/content/media/456845-212011-30021-PM-1339536743.png
it all has to add up to 540 degrees. So....
Ok care to explain please this is the last one I have trouble with :(
Use the same approach I showed above: You get (180-360/5)*5 = (180-72)*5 = 108*5 = 540 degrees. Sum of all five angles should be 540 degrees. So, you get an equation in x and solve for x.

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