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anonymous
 4 years ago
Find the distance between (1, 2) and (4, 3).
anonymous
 4 years ago
Find the distance between (1, 2) and (4, 3).

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UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328837842980:dw

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.0so we have a right angle triangle and we need the hypotenuse(diagonal) length \[2^2+2^2=d^2\] \[d=√(4+4)\] \[d=√8\] \[=2√2\] ok so it looks like i ploted the wrong points but you get the method right?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0distance is NOT a point. it is a measure between 2 points. what I like to do is move the points so that one of them is at the origin (0,0); and what you do to one point you have to do to them all ... ( 1,2) (4, 3) 1 +2 1+2   (0,0) (5,5) we can read this now as moving from the origin; over 5 and up 5; distance is determined by squaring your distances moved; adding them up; and sqrting the results; its a consequence of the pythagoraen thrm. (5)^2 = 25 (5)^2 = 25  50; sqrt(50) = 5sqrt(2) our distance is 5sqrt(2)
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