Find the distance between (1, -2) and (-4, 3).

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Find the distance between (1, -2) and (-4, 3).

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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so we have a right angle triangle and we need the hypotenuse(diagonal) length \[2^2+2^2=d^2\] \[d=√(4+4)\] \[d=√8\] \[=2√2\] ok so it looks like i ploted the wrong points but you get the method right?
so (2,2)

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distance is NOT a point. it is a measure between 2 points. what I like to do is move the points so that one of them is at the origin (0,0); and what you do to one point you have to do to them all ... ( 1,-2) (-4, 3) -1 +2 -1+2 ------ ----- (0,0) (-5,5) we can read this now as moving from the origin; over -5 and up 5; distance is determined by squaring your distances moved; adding them up; and sqrting the results; its a consequence of the pythagoraen thrm. (-5)^2 = 25 (5)^2 = 25 ------ 50; sqrt(50) = 5sqrt(2) our distance is 5sqrt(2)

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