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anonymous

  • 4 years ago

Find the distance between (1, -2) and (-4, 3).

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  1. UnkleRhaukus
    • 4 years ago
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    |dw:1328837842980:dw|

  2. UnkleRhaukus
    • 4 years ago
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    so we have a right angle triangle and we need the hypotenuse(diagonal) length \[2^2+2^2=d^2\] \[d=√(4+4)\] \[d=√8\] \[=2√2\] ok so it looks like i ploted the wrong points but you get the method right?

  3. anonymous
    • 4 years ago
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    so (2,2)

  4. amistre64
    • 4 years ago
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    distance is NOT a point. it is a measure between 2 points. what I like to do is move the points so that one of them is at the origin (0,0); and what you do to one point you have to do to them all ... ( 1,-2) (-4, 3) -1 +2 -1+2 ------ ----- (0,0) (-5,5) we can read this now as moving from the origin; over -5 and up 5; distance is determined by squaring your distances moved; adding them up; and sqrting the results; its a consequence of the pythagoraen thrm. (-5)^2 = 25 (5)^2 = 25 ------ 50; sqrt(50) = 5sqrt(2) our distance is 5sqrt(2)

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