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anonymous

  • 4 years ago

After t hours, Liza's distance from home, in miles, is given by D(t) = 138 + 40(t-3) what is the practical interpretation of the constants 3 and 138?

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  1. sasogeek
    • 4 years ago
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    i'm not sure if this is right but here's what i think and i'll let someone confirm or provide the correct answer... from y=mx+c I believe that 138 is the distance she was away from home after 3 seconds.

  2. asnaseer
    • 4 years ago
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    after t "hours"

  3. IsTim
    • 4 years ago
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    thought she was that far (138) at the beginning.

  4. IsTim
    • 4 years ago
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    When t=0

  5. asnaseer
    • 4 years ago
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    no IsTim - sasogeek is right (except for the units of time).

  6. sasogeek
    • 4 years ago
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    40*3 would change the distance when t=0

  7. IsTim
    • 4 years ago
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    Sigh. IsTim is wrong again.

  8. sasogeek
    • 4 years ago
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    but IsTim has learnt now :D

  9. asnaseer
    • 4 years ago
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    well put saso :D

  10. anonymous
    • 4 years ago
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    Thanks for your help guys

  11. sasogeek
    • 4 years ago
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    anytime ;)

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