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Blue_Bunny

  • 4 years ago

x^3+27+0 please factor with steps

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  1. smurfy14
    • 4 years ago
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    27+0? or is there another x?

  2. mattt9
    • 4 years ago
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    no his question is right

  3. moneybird
    • 4 years ago
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    (x+3)(x^2 -3x +9)

  4. moneybird
    • 4 years ago
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    +0 is kinda weird

  5. mattt9
    • 4 years ago
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    math textbooks are kinda weird. lol

  6. Blue_Bunny
    • 4 years ago
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    i meant =0 my bad

  7. moneybird
    • 4 years ago
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    (x+3)(x^2 -3x +9) = 0 x + 3 = 0 x = -3 x^2 -3x +9 = 0

  8. StArAnGeL
    • 4 years ago
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    \[x^3+27=0\]\[\mathsf { We \ Can \ write \ it \ as \ (x)^3 + (3)^3 =0 } \]\[\mathsf {Now \ use \ the \ formula \ (x)^3 + (y)^3= (x+y)(x^2-xy+y^2)} \] \[\mathsf {(x+3)(x^2 -3x +9) = 0}\]\[\mathsf {x + 3 = 0 \ and \ x^2-3x+9=0 }\]\[\mathsf {x = -3} \] \[ \mathsf { x^2-3x+9=0 }\]

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