A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
A 34.3 kg block (m1) is on a horizontal surface, connected to a 6.3 kg block (m2) by a massless string as shown in the Figure. The pulley is massless and frictionless. A force of 216.9 N acts on m1 at an angle of 31.5°. The coefficient of kinetic friction between m1 and the surface is 0.189. Determine the upward acceleration of m2.
anonymous
 4 years ago
A 34.3 kg block (m1) is on a horizontal surface, connected to a 6.3 kg block (m2) by a massless string as shown in the Figure. The pulley is massless and frictionless. A force of 216.9 N acts on m1 at an angle of 31.5°. The coefficient of kinetic friction between m1 and the surface is 0.189. Determine the upward acceleration of m2.

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0acceleration of m2 is acceleration of system dw:1328975564405:dw iget left along +, so \[Fcos \thetaTf=m _{1}a\]where \[f=\mu _{k}N \]\[N+Fsin \theta=m _{1}g\] \[Tm _{2}g=m _{2}a\] so we have two equation with 2 passive ,set T & N in 2nd law & solve this for a this ask is aspecial case of Atwood system with friction .
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.