anonymous 4 years ago A 34.3 kg block (m1) is on a horizontal surface, connected to a 6.3 kg block (m2) by a massless string as shown in the Figure. The pulley is massless and frictionless. A force of 216.9 N acts on m1 at an angle of 31.5°. The coefficient of kinetic friction between m1 and the surface is 0.189. Determine the upward acceleration of m2.

acceleration of m2 is acceleration of system |dw:1328975564405:dw| iget left along +, so $Fcos \theta-T-f=m _{1}a$where $f=\mu _{k}N$$N+Fsin \theta=m _{1}g$ $T-m _{2}g=m _{2}a$ so we have two equation with 2 passive ,set T & N in 2nd law & solve this for a this ask is aspecial case of Atwood system with friction .