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sammy12
 3 years ago
If xy = 6 and x^2 + y^2 = 16, then what is the value of (x + y)?
sammy12
 3 years ago
If xy = 6 and x^2 + y^2 = 16, then what is the value of (x + y)?

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ChrisV
 3 years ago
Best ResponseYou've already chosen the best response.1im trying to remember how to do this one sec

lazypig
 3 years ago
Best ResponseYou've already chosen the best response.2\[x ^{2}+y ^{2}+2xy =16+6\times2\] \[\left( x +y \right)^{2}=28\] \[x +y =\pm \sqrt{28}\]

ChrisV
 3 years ago
Best ResponseYou've already chosen the best response.1dunno how you came up with that but no way that works

ChrisV
 3 years ago
Best ResponseYou've already chosen the best response.1its obvious the values of x and y are 2 and 3 but i cannot for the life of me remember how to explain it

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.0\[(x+y)^2=x^2+2xy+y^2=x^2+y^2+2(xy)=16+2(6)=16+12=28\] so we have \[(x+y)^2=28 => x+y=\pm \sqrt{28}\]

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.0so i agree with lazy :)
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