Can someone help with finding the velocity of this?? I don't understand.

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Can someone help with finding the velocity of this?? I don't understand.

Physics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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It's question 8... http://xtremepapers.com/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_s10_qp_11.pdf
Slope of tangent of velocity-time graph gives accelaration. V at any instant 't' = dv/dt at 't' Hope you know what to do next.
um, I don't really know, do you know what the answer is?

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Hi first you ought find V equation & differentiate from it proportion t to reaching acceleration equation in general V is\[V=bt ^{2}+ct+V _{0}\] we know v0=4 if you differentiate from V yields\[a=2bt+c\] in t=0 a=0 so reaches c=0 now V equation is\[V=bt ^{2}+4\] from graph we can find b so b=.222222222222222222222 finally V is:\[0.22222222t ^{2}+4\] differentiate proportion t from above & find acceleration on t=3 i find 1.3

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