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beth12345

  • 4 years ago

Can someone help with finding the velocity of this?? I don't understand.

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  1. beth12345
    • 4 years ago
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    It's question 8... http://xtremepapers.com/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_s10_qp_11.pdf

  2. anonymous
    • 4 years ago
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    Slope of tangent of velocity-time graph gives accelaration. V at any instant 't' = dv/dt at 't' Hope you know what to do next.

  3. beth12345
    • 4 years ago
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    um, I don't really know, do you know what the answer is?

  4. anonymous
    • 4 years ago
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    Hi first you ought find V equation & differentiate from it proportion t to reaching acceleration equation in general V is\[V=bt ^{2}+ct+V _{0}\] we know v0=4 if you differentiate from V yields\[a=2bt+c\] in t=0 a=0 so reaches c=0 now V equation is\[V=bt ^{2}+4\] from graph we can find b so b=.222222222222222222222 finally V is:\[0.22222222t ^{2}+4\] differentiate proportion t from above & find acceleration on t=3 i find 1.3

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