beth12345
  • beth12345
Can someone help with finding the velocity of this?? I don't understand.
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
beth12345
  • beth12345
It's question 8... http://xtremepapers.com/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_s10_qp_11.pdf
anonymous
  • anonymous
Slope of tangent of velocity-time graph gives accelaration. V at any instant 't' = dv/dt at 't' Hope you know what to do next.
beth12345
  • beth12345
um, I don't really know, do you know what the answer is?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Hi first you ought find V equation & differentiate from it proportion t to reaching acceleration equation in general V is\[V=bt ^{2}+ct+V _{0}\] we know v0=4 if you differentiate from V yields\[a=2bt+c\] in t=0 a=0 so reaches c=0 now V equation is\[V=bt ^{2}+4\] from graph we can find b so b=.222222222222222222222 finally V is:\[0.22222222t ^{2}+4\] differentiate proportion t from above & find acceleration on t=3 i find 1.3

Looking for something else?

Not the answer you are looking for? Search for more explanations.